Help on Special Right Triangles!? Trignometry!! Help Plz!?
How do I solve the right triangle ABC with right angle C, a=39.45ft and b=6.32ft.
Please explain, I really want to learn!
How do I solve the right triangle ABC with right angle C, a=39.45ft and b=6.32ft.
Please explain, I really want to learn!
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Are you trying to find SIDE c? Because you would use the Pythagorean theorem to find it. a^2 + b^2 = c^2. 39.45ft^2 + 6.32ft^2 = the square root of C . C = 1596.2449. the sqaure root of 1596.2449 is 39.9530336771. So your answer is SIDE C = 40ft.
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Solving a right triangle consists of finding out all six parts of the right triangle. (three side lengths and three angle measures). You are given 3 of these.
You know side length a, side length b, and angle measure of C.
You need to know side length c and the angle measures of A and B.
As others have posted, doing the Pythagorean Theorem will give you side length c. To do this square and then add the side lengths of a and b. Square root your sum and you will get the side length of c. In you example, 39.45^2 + 6.32^2 = 1596.2449. Take the square root of this number and you get the side length of c sq. rt of 1596.2449 = 39.953033677056364426634135503415 (round accordingly).
That takes care of the sides. Now we need to find the angle measures. You already know that angle C is 90 degrees. To find angle A and angle B we need to do trig ratios. The side opposite angle A should be a, the side opposite (across from) angle B should be b. Since the known leg lengths were the legs of the right triangle, we need to use the tangent function (because sine and cosine use the hypotenuse which we are rounding and we never want to use rounded figures to calculate other figures). Since we are looking for angle measures by using side lengths, we need to use the inverse tangent function. Tangent is opposite over adjacent, so to find angle A, we are going to do tan^-1 = 39.45/6.32 and to find angle B, we are going to do tan^-1 = 6.32/39.45. When we do this, we find out angle A is 80.898394541464223333205391352317 degrees and angle B is 9.1016054585357766667946086476832 degrees.
You know side length a, side length b, and angle measure of C.
You need to know side length c and the angle measures of A and B.
As others have posted, doing the Pythagorean Theorem will give you side length c. To do this square and then add the side lengths of a and b. Square root your sum and you will get the side length of c. In you example, 39.45^2 + 6.32^2 = 1596.2449. Take the square root of this number and you get the side length of c sq. rt of 1596.2449 = 39.953033677056364426634135503415 (round accordingly).
That takes care of the sides. Now we need to find the angle measures. You already know that angle C is 90 degrees. To find angle A and angle B we need to do trig ratios. The side opposite angle A should be a, the side opposite (across from) angle B should be b. Since the known leg lengths were the legs of the right triangle, we need to use the tangent function (because sine and cosine use the hypotenuse which we are rounding and we never want to use rounded figures to calculate other figures). Since we are looking for angle measures by using side lengths, we need to use the inverse tangent function. Tangent is opposite over adjacent, so to find angle A, we are going to do tan^-1 = 39.45/6.32 and to find angle B, we are going to do tan^-1 = 6.32/39.45. When we do this, we find out angle A is 80.898394541464223333205391352317 degrees and angle B is 9.1016054585357766667946086476832 degrees.
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Pythagorean theorem:
a^2 + b^2 = c^2
39.45^2 + 6.32^2 = c^2
1556.3 + 39.9 = c^2
1596.2 = c^2
c = sq rt of 1596.2 or 39.95
a^2 + b^2 = c^2
39.45^2 + 6.32^2 = c^2
1556.3 + 39.9 = c^2
1596.2 = c^2
c = sq rt of 1596.2 or 39.95