Can someone tell me what is the STANDARD Form of 3| x + 3| - 9 = 0 Please

please help, thanks!

3|x+3|-9=0
+9 to each side
3|x+3|=9
divide each side by 3
|x+3|=3
that is the standard form

to solve:
|x+3|=3
x+3=3
OR
x+3 = -3

x=0
OR
x=-6

Not sure what you mean.

Usually an equation is written with all the variables on the left and everything else on the right.

You have to remember that when you see |x| you see x and -x

So, what you have here is:

3| x + 3| - 9 = 0
=> | x + 3| - 9 = 0
=> (x + 3) - 9 = 0

and

=> -(x + 3) - 9 = 0

So, in essence you have 2 equations.

(1) x + 3 = 9
(2) -x - 3 = 9


Make sense?

Absolute value of a number is defined by two equations; Abs x = x, when x> or = 0
Abs x = -x when x<0

Therefore the standasrd form of this equation is called a piecewise funtion defined follows:

3(x+3) - 9 = 0 -----> 3x + 3 -9 = 0 ------> 3x -6 when x> or = 0
&
3(-x + 3) - 9 = 0 ----> -3x -3 -9 = 0 -----> -3x - 12 when x< 0

Hint: Think of the definition of absolute value of x + 3:

| x + 3 | = x + 3, if x + 3 > 0, or x > -3

| x + 3 | = -(x + 3), if x + 3 < 0, or x < - 3

| x + 3 | = 0, if (x + 3) =0, or x = -3

3 | x + 3 | − 9 = 0

3 | x + 3 | = 9

| x + 3 | = 3

x + 3 = ± 3

x = −3 ± 3

x = −6, x = 0

That is the standard form