if x = 2 and y = -2, then what is the value of x^2 - y^2
Explain your steps.
:)
Explain your steps.
:)
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Ok Lily---
The answer is 0 and here's why.
x^2 = 2^2 = 4
y^2 = (-2)^2 = 4
and x^2 - y^2 = 4- 4 = 0.
The answer is 0 and here's why.
x^2 = 2^2 = 4
y^2 = (-2)^2 = 4
and x^2 - y^2 = 4- 4 = 0.
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Zero. 2 times 2 equals 4. -2 times -2 equals 4 bc negative times negative is positive. So 4 - 4 equals zero. Anything squared is just it times itself, to elaborate.
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Yes, very easy points...
4 - 4 = 0
There really are no steps to explain. What is 2 squared? What is -2 squared? 4 and 4. So... 4 - 4 = 0
4 - 4 = 0
There really are no steps to explain. What is 2 squared? What is -2 squared? 4 and 4. So... 4 - 4 = 0
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assuming that ^ means: "to the power of" -- then the value of x^2 - y^2 = 0
2^2 = 4
-2^2 = 4
4 - 4 = 0
2^2 = 4
-2^2 = 4
4 - 4 = 0
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0
2^2-(-2)^2
4-4
0
2^2-(-2)^2
4-4
0
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2^2 - (-2)^2 = 4-4 = 0
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x^2-y^2
= (2)^2 - (-2)^2 [x=2, y=-2]
= 4-4
= 0
= (2)^2 - (-2)^2 [x=2, y=-2]
= 4-4
= 0
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wtf is ^ meant to be?