I just want to make sure this isn't a trick question or something...
Find F'(x):
F(x) = Integral (7tan(t)) dt
And the upper thing of the integral is x and the lower thing is 0. (sorry, if forgot what the "things" were called)
I got 7tan(x) as my answer cause the derivative and the integral cancel out... right?
Thanks in advance for all answers and 10 points to best answer with work!
Find F'(x):
F(x) = Integral (7tan(t)) dt
And the upper thing of the integral is x and the lower thing is 0. (sorry, if forgot what the "things" were called)
I got 7tan(x) as my answer cause the derivative and the integral cancel out... right?
Thanks in advance for all answers and 10 points to best answer with work!
-
According to the fundamental theorem of calculus, yes you are correct.
Do note though you may run into something like d/dx ∫{0,x^2} 7 tan(t)
= 2x7tan(x^2) = 14xtan(x^2)
Do note though you may run into something like d/dx ∫{0,x^2} 7 tan(t)
= 2x7tan(x^2) = 14xtan(x^2)
-
Since F(t) = int F'(t)dt, if F(x) = int 7tan(t)dt, then F'(x) = 7tan(x)