What is the partial pressure of SO2 produced if the total gas pressure after the reaction is complete is 795 mmHg?
2SO3(g)--->2SO2(g)+02(g)
Can you please explain how you got the answer step by step.
Thank you so much!!
2SO3(g)--->2SO2(g)+02(g)
Can you please explain how you got the answer step by step.
Thank you so much!!
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2 SO3 → 2 SO2(g) + O2(g)
There are 3 moles of gases total in the final state. Of those, 2 moles are SO2.
So 2/3 of the total pressure is due to SO2.
(795 mmHg) x (2/3) = 530 mmHg SO2
There are 3 moles of gases total in the final state. Of those, 2 moles are SO2.
So 2/3 of the total pressure is due to SO2.
(795 mmHg) x (2/3) = 530 mmHg SO2