http://prntscr.com/bmtnk
find csc(t)
well I got 5* sqrt(24)/24
but non of the answer matches, please help
find csc(t)
well I got 5* sqrt(24)/24
but non of the answer matches, please help
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Technically your answer is correct. You did not put negative since csc is negative in III quadrant and you have not simplified your answer
cos t = -1/5 and t is in III quadrant
since cos is adjacent side / hypotenuse , adjacent side = 1 and hypotenuse = 5
opposite side = SQRT(5^2 - 1^2) = SQRT(25 - 1) = SQRT(24) = 2√6
csc t = hypotenuse / opposite side = - 5 / 2√6 = - (5/12)√6 ( csc is negative in III quadrant )
cos t = -1/5 and t is in III quadrant
since cos is adjacent side / hypotenuse , adjacent side = 1 and hypotenuse = 5
opposite side = SQRT(5^2 - 1^2) = SQRT(25 - 1) = SQRT(24) = 2√6
csc t = hypotenuse / opposite side = - 5 / 2√6 = - (5/12)√6 ( csc is negative in III quadrant )
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t is in Q III so csc(t) is negative.
opposite side = -sqrt(24)
csc(t) = -5sqrt(24)/24
csc(t) = -10sqrt(6)24=
-5sqrt(6)/12
opposite side = -sqrt(24)
csc(t) = -5sqrt(24)/24
csc(t) = -10sqrt(6)24=
-5sqrt(6)/12