What is the equation in point-slope form of the line passing through (2, 5) and (–1, 8)?
Answer
y + 8 = –1(x – 1)
y – 8 = 1(x – 2)
y – 5 = –1(x – 2)
y + 5 = 1(x + 2)
Answer
y + 8 = –1(x – 1)
y – 8 = 1(x – 2)
y – 5 = –1(x – 2)
y + 5 = 1(x + 2)
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First use the points (x1,y1) = (2,5) and (x2,y2) = (-1,8) to find the slope:
m = (y2 - y1) / (x2 - x1)
m = (8 - 5) / (-1 - 2)
m = 3 / -3
m = -1
Now use the point (x1,y1) = (2,5) and the slope m = -1 to write the equation:
y - y1 = m(x - x1)
y - 5 = -1(x - 2)
So, the answer is y - 5 = -1(x - 2).
Hope that helps! :)
m = (y2 - y1) / (x2 - x1)
m = (8 - 5) / (-1 - 2)
m = 3 / -3
m = -1
Now use the point (x1,y1) = (2,5) and the slope m = -1 to write the equation:
y - y1 = m(x - x1)
y - 5 = -1(x - 2)
So, the answer is y - 5 = -1(x - 2).
Hope that helps! :)
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y - y1 = m(x - x1)
8-5=m(-1-2)
3=m(-3)
3/-3=-1=m
y – 5 = –1(x – 2)
8-5=m(-1-2)
3=m(-3)
3/-3=-1=m
y – 5 = –1(x – 2)