Solving right triangles problem...
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Solving right triangles problem...

[From: ] [author: ] [Date: 12-01-10] [Hit: ]
To solve for L, I have to take the inverse cosine of each side. However, this is impossible, due to the fact that the domain restriction of arccos(x) is -11. Please help!......
Two sides of a right triangle are given: 7 and 13, where 13 is the hypotenuse of the triangle. I found the third side to be 2*sqrt(30) using the Pythagorean theorem. The missing angle I have to find is labelled L. Using trigonometry, I decided that cos L = [2*sqrt(30)]/13. To solve for L, I have to take the inverse cosine of each side. However, this is impossible, due to the fact that the domain restriction of arccos(x) is -11. Please help!

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Bro your complicated yourself lol.... You got all the sides of the triangle and an angle (90 degrees). Just use the Law of Sines and you can figure out the other two missing angles. Sin (90) / 13 = Sin L / 7 or Sin (90) / 13 = Sin 2(rad30) / 2 depending on what L represents.... 32.57 or 57.43 can be the answers depending on what L represents
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