Evaluate g[f(-2)] and f[g(3)] for each pair of functions.

(first)
F(x) = 3x, g(x) = 2x + 3


(second)
F(x) = -x , g(x) = x + 5

(first)
f(x) = 3x, g(x) = 2x + 3

g[f(-2)] = g[ 3(-2) ] = g( -6) = 2(-6) +3 = -9
f[g(3)] = f[ 2(3) +3] = f(9) = 3(9) = 27

(second)
f(x) = -x , g(x) = x + 5
g[f(-2)] = g[ -(-2) ] = g(2) = (2) + 5 = 7
f[g(3)] = f[ (3) +5 ] = f(8) = -(8) = -8

(first)
F(-2)=3((-2)--> -6
g(3)=2(3)+3-->6+3-->9

second
F(-2)=-(-2)=2 and g(3)=3+5=8