1.) Ed has a garden box he would like to fill with potting soil. The dimensions of the box are 5 yards long by 2 yards wide and 8 inches deep. A store sells potting soil in bags where each bag contains one cubic foot of soil. How many bags does Ed need to purchase?
2.) For shipment purposes, a basketball is packaged in a cubed box. The circumference of the basketball is 28.5 inches. What is the volume of the smallest cubed box that will hold the basketball? Answer to the nearest cubic inch.
3.) A cylinder has a surface area of 339 cm^2. The radius is two times greater than the height. What is the radius of the cylinder? Answer to the nearest cm.
please show your work! i will choose the best answer instantly!
2.) For shipment purposes, a basketball is packaged in a cubed box. The circumference of the basketball is 28.5 inches. What is the volume of the smallest cubed box that will hold the basketball? Answer to the nearest cubic inch.
3.) A cylinder has a surface area of 339 cm^2. The radius is two times greater than the height. What is the radius of the cylinder? Answer to the nearest cm.
please show your work! i will choose the best answer instantly!
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1) V = L*W*H
..........5yd * 2yd * 8in................change all to FEET
..........5*3 ft * 2*3 ft * 8*(1/12)ft
..........15ft * 6ft * (2/3)ft
V = 60 ft^3
ANSWER 60 bags
2) C = 2(pi)r
....28.5 = 2(pi)r
r = 28.5/(2pi)
r = 4.535915878 ~ ~
edge of box = 2r = 9.071831756 in
V = (2r)^3
ANSWER....V = 746.59 in^3
3) SA = pi(r^2)h + 2(pi)r^2........r=2h....OR.....h=0.5r
339 = pi(r^2)(0.5r) + 2(pi)r^2
(,5*pi)r^3 + (2*pi)r^2 - 339 = 0
r = 4.919 cm
I tutor free online since moving to France from Florida in June 2011.
Hope this is most helpful and you will continue to allow me to tutor you.
If you dont fully understand or have a question PLEASE let me know
how to contact you so you can then contact me directly with any math questions.
If you need me for future tutoring I am not allowed to give out my
info but what you tell me on ***how to contact you*** is up to you
Been a pleasure to serve you Please call again
Robert Jones.............f
"Teacher/Tutor of Fine Students"
..........5yd * 2yd * 8in................change all to FEET
..........5*3 ft * 2*3 ft * 8*(1/12)ft
..........15ft * 6ft * (2/3)ft
V = 60 ft^3
ANSWER 60 bags
2) C = 2(pi)r
....28.5 = 2(pi)r
r = 28.5/(2pi)
r = 4.535915878 ~ ~
edge of box = 2r = 9.071831756 in
V = (2r)^3
ANSWER....V = 746.59 in^3
3) SA = pi(r^2)h + 2(pi)r^2........r=2h....OR.....h=0.5r
339 = pi(r^2)(0.5r) + 2(pi)r^2
(,5*pi)r^3 + (2*pi)r^2 - 339 = 0
r = 4.919 cm
I tutor free online since moving to France from Florida in June 2011.
Hope this is most helpful and you will continue to allow me to tutor you.
If you dont fully understand or have a question PLEASE let me know
how to contact you so you can then contact me directly with any math questions.
If you need me for future tutoring I am not allowed to give out my
info but what you tell me on ***how to contact you*** is up to you
Been a pleasure to serve you Please call again
Robert Jones.............f
"Teacher/Tutor of Fine Students"
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1.)
5 yards = 5*3 = 15 feet
2 yards = 2*3 =6 feet
8 inches = 8 *0.08333 = 0.666 ft
Volume: 15*6*0.666 = 59.994 cubic feet
===> 60 bags of 1 cubic feet each
2.
pi*d = 28.5 ==> d = 9.071
V = 9.071^3 = 747 cubic inches
3.
2pi*r^2 + 2pi*r *h = 339
r = 2h ==> h = r/2
2pi*r^2 + 2*pi*r * r/2 = 339
3pi r^2 = 339
r = sqrt(339/3) = 10.63 = 11 cm
5 yards = 5*3 = 15 feet
2 yards = 2*3 =6 feet
8 inches = 8 *0.08333 = 0.666 ft
Volume: 15*6*0.666 = 59.994 cubic feet
===> 60 bags of 1 cubic feet each
2.
pi*d = 28.5 ==> d = 9.071
V = 9.071^3 = 747 cubic inches
3.
2pi*r^2 + 2pi*r *h = 339
r = 2h ==> h = r/2
2pi*r^2 + 2*pi*r * r/2 = 339
3pi r^2 = 339
r = sqrt(339/3) = 10.63 = 11 cm
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