Here's the work...
Divide and check.
12a^3b^2+4a^4b^5+16 a b^2/4 a b^2
check for the lowest power of a and for b, and factorize accordingly
ab^2(12a + 4a^3b^3 + 16) / (4ab^2) = (12a + 4a^3b^3 + 16)/4
rewrite each numerical member of the denominator in terms of its factors
(3*4*a + 4*1*a^3b^3 + 4^2)/4
factorize by 4
4(3a + a^3b^3 + 4) / 4 = 3a + a^3b^3 + 4
I need to know how to check it from here. Please show all of your work so I can understand how to do it. Thank you!
Divide and check.
12a^3b^2+4a^4b^5+16 a b^2/4 a b^2
check for the lowest power of a and for b, and factorize accordingly
ab^2(12a + 4a^3b^3 + 16) / (4ab^2) = (12a + 4a^3b^3 + 16)/4
rewrite each numerical member of the denominator in terms of its factors
(3*4*a + 4*1*a^3b^3 + 4^2)/4
factorize by 4
4(3a + a^3b^3 + 4) / 4 = 3a + a^3b^3 + 4
I need to know how to check it from here. Please show all of your work so I can understand how to do it. Thank you!
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12a^3b^2+4a^4b^5+16 a b^2/4 a b^2
4ab^2(3a^2 + a^3b^3 + 4)4ab^2
cancel out 4ab^2 on both numerator and denominator
3a^2 + a^3b^3 + 4
your answer has a slight error on the first term. it must be 3a^2 not 3a
4ab^2(3a^2 + a^3b^3 + 4)4ab^2
cancel out 4ab^2 on both numerator and denominator
3a^2 + a^3b^3 + 4
your answer has a slight error on the first term. it must be 3a^2 not 3a