Chem Help[Excess Reactant Mass]
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Chem Help[Excess Reactant Mass]

[From: ] [author: ] [Date: 11-12-21] [Hit: ]
What do I do to figure out with this information to find the mass in grams of the excess reactant?What is the formula I would use?Any chem experts wanna share their knowledge with me?-It is simpler knowing Cl2 is limiting.It is .Mols Al left over = .......
Here's the question:
"What mass of the excess reactant will remain when the reaction is complete?
2Al(s) + 3Cl2(g) = Al2Cl6(s)
Given:
0.100 mol Al
0.0571 mol Cl2
Cl2 is the limiting reagent
5.08g Al2Cl6 produced"

What do I do to figure out with this information to find the mass in grams of the excess reactant? What is the formula I would use?
Any chem experts wanna share their knowledge with me?

-
It is simpler knowing Cl2 is limiting.
Just see how many mol of Al would react with the given amount of Cl2
It is .0571 x [2/3] = you calculate it
Mols Al left over = .1 minus Al consumed
Then multiply by atomic mass Al to get mass


As a check, convert 5.08g Al2Cl6 into moles and double that to find how many mol Al were used, then subtract from .1
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