please explain how to do this please so i could finish the rest of my homework by myself.
how many grams of each of the following must be dissolved with enough water to produce 625 mL of a solution, so the concentration of 2.50 mols/L?
1) K (subscript 2) S
2) HF
what volume of the following solutions would contain the amount of solute given? give answer in both L and mL
a 0.50 M solution of LiOH containing 1.2 moles of solute.
I will vote best answer so you could get points. thank you
how many grams of each of the following must be dissolved with enough water to produce 625 mL of a solution, so the concentration of 2.50 mols/L?
1) K (subscript 2) S
2) HF
what volume of the following solutions would contain the amount of solute given? give answer in both L and mL
a 0.50 M solution of LiOH containing 1.2 moles of solute.
I will vote best answer so you could get points. thank you
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Molarity = moles/Liters
In the problem, liters is given as ml, so convert it to .625 L.
substitute the known values into the equation M = mol/L
That will give you the number of moles you need of the solvent (K2S or HF). Then, multiply the number of moles by the molar mass of that solvent to get the number of grams needed.
To start your problem off,
2.50M= mol / .625 L
mol = 1.5625. This is the number of moles needed of each solvent. Now multiply by the molar mass of whichever solvent you are solving for.
2. M= mol/L (volume), and two of the variables are given. Substitute:
.50M= 1.2 / L
and solve for the amount of Liters.
In the problem, liters is given as ml, so convert it to .625 L.
substitute the known values into the equation M = mol/L
That will give you the number of moles you need of the solvent (K2S or HF). Then, multiply the number of moles by the molar mass of that solvent to get the number of grams needed.
To start your problem off,
2.50M= mol / .625 L
mol = 1.5625. This is the number of moles needed of each solvent. Now multiply by the molar mass of whichever solvent you are solving for.
2. M= mol/L (volume), and two of the variables are given. Substitute:
.50M= 1.2 / L
and solve for the amount of Liters.
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molarity = moles / liters
molarity x liters = moles
625 mL = 0.625 L
2.50 mol/L x 0.625 L = 1.5625 mole
K2S molar mass = 110.27 g/mole
1.5625 mole x 110.27 g/mole = 172.3 g K2S
molarity = moles / liters
0.50 M = 1.2 mole / L
L = 1.2 mole /0.50 mol/L = 2.4 L
molarity x liters = moles
625 mL = 0.625 L
2.50 mol/L x 0.625 L = 1.5625 mole
K2S molar mass = 110.27 g/mole
1.5625 mole x 110.27 g/mole = 172.3 g K2S
molarity = moles / liters
0.50 M = 1.2 mole / L
L = 1.2 mole /0.50 mol/L = 2.4 L