Need help with math problems

Lol sorry, I forgot most of this stuff and really need the help. I REALLY NEED THE WORK SHOWN PLEASE. I MEAN REALLY "I REALLY NEED WORK SHOWN."

2 3/4 x 3

7/10 - 1/6

6 x 8/21

8 4/7 - 1 5/14

5 3/4 + 6 1/3

11 1/3 x 7 5/12

1/16 ÷ 8 3/4

solve each equation. Check your solution

y/3.7 = 8.1

6 = 2/5 m

3/4 = 5/8x

3 1/6 = 2/3p

1. Make 2 3/4 an improper fraction. This is the denominator times the whole number plus the numerator, all over the denominator. 2 3/4 = (4*2+3)/4 = 11/4
Make 3 an improper fraction also. That is 3/1.
When multiplying fractions, multiply the first numerator and the second numerator and divide that by the first denominator multiplied with the second denominator. 11/4 x 3/1 = (11x3)/(4x1) = 33/4

2. Make both the first and the second fractions have common denominators by finding their least common multiple (LCM), specifically the least possible. 10 and 6 have an LCM of 30.
To make 7/10 have a denominator of 30, multiply both the numerator and denominator by 3 (30÷10). 7/10 = (7x3)/(10x3) = 21/30
To make 1/6 have a denominator of 30, multiply both the numerator and denominator by 5 (30÷6). 1/6 = (1x5)/(6x5) = 5/30
The way to subtract fractions is to subtract the second numerator from the first numerator and leave it over the same denominator. 21/30 - 5/30 = (21-5)/30 = 16/30. This can be simplified. To simplify, divide by the numerator and denominator's greatest common factor (GCF). The GCF of 16 and 30 is 2. 16/30 = (16÷2)/(30÷2) = 8/15

3. This is the same as #1. Just make 6 an improper fraction (6/1) and multiply like you did before. 6/1 x 8/21 = (6x8)/(1x21) = 48/21.
If you need this to be written in mixed number form, divide 21 from 48, make the whole value the whole number, and make the remainder the numerator. Leave the denominator 21.
48/21 = 2 r6 = 2 6/21

4. Follow the steps of #1 to make these values improper fractions.