A flywheel rotating at 210 rev/min is accelerated uniformaly for 4 seconds until its speed is 300 rev/min

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A flywheel rotating at 210 rev/min is accelerated uniformaly for 4 seconds until its speed is 300 rev/min

[From: ] [author: ] [Date: 11-12-21] [Hit: ]

Use, ωf = ωo + a*t ,After finding the angular acceleration. you can use the formula analygous to S = Vo*t + 1/2*a*t^2 for linear motion to calculate the number of revolutions made by the flywheel in 4 seconds.......

Determine angular acceleration
Determine the number of revolutions made by the flywheel in 4 seconds

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1. Angular acceleration = (change in angular speed)/(time)
= (2π/60).(300-210)/4 = 2.356 radians/s²

2. Average speed during this 4 seconds = 255 rpm = 255/60 revs/s
So number of revolutions made = 4 x 255/60 = 17.

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First change engineering angular speeds to scientific:
ωo = 210 rev/min * 2*π/60 = 21.99 rad/s
ωf = 300 rev/min * 2*π/60 = 31.416rad/s
Use, ωf = ωo + a*t , Where a is the angular acceleration
After finding the angular acceleration. you can use the formula analygous to S = Vo*t + 1/2*a*t^2 for linear motion to calculate the number of revolutions made by the flywheel in 4 seconds.

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