Factor 40x^2 - 4x -12

I'm confused with my homework if I can get help on this I can do the rest of my work

Use the Quadratic Equation. If you haven't learned it yet, you'll see it's a foolproof way to answer your polynomial questions

the equation is
For any problem of the form Ax^2 ± Bx ± C, where A, B, and C are Coefficients

x= { -b ± SQRT(b^2 - 4ac) } all over 2A

So here, it would be

-(-4) ± sqrt((-4)^2 - (4)(40)(-12)) all over (2*40)

this works out to be

+4 ± 44 all over 80

4+44 = 48.....48/80 = 0.6
4-44= -40.....-40/80 = -1/2

hope this helps!

40x^2-4x-12=0
divide both sides by 4 to simplify.
10x^2-x-3=0
10x^2 +5x-6x-3=5x(2x+1)-3(2x+1)=(5x-3)(2x+1)

what is the greatest common factor

4(10x^2-x-3)

4(5x-3)(2x+1)

OK set this equal to zero and us the quadratic formula to find your answer. For more help
http://www.regentsprep.org/Regents/math/algtrig/ATE3/quadformula.htm

4*(10*x^2 - x - 3) = 4*(5*x - 3 )*(2*x + 1)