x^3+4x^2+x+4
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All you have to do here is group:
(x³+4x²) + (x+4)
Then, GCF the first group (second one is already in its simplest form):
x²(x+4) + (x+4)
Last, complete (simplify):
(x+4)(x²+1)
(x³+4x²) + (x+4)
Then, GCF the first group (second one is already in its simplest form):
x²(x+4) + (x+4)
Last, complete (simplify):
(x+4)(x²+1)
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Use grouping
(x^3+4x^2)+(x+4)
Factor the GCF from each parenthesis
x^2(x+4)+1(x+4)
Factor (x+4)
(x+4)(x^2+1)
(x^3+4x^2)+(x+4)
Factor the GCF from each parenthesis
x^2(x+4)+1(x+4)
Factor (x+4)
(x+4)(x^2+1)
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x^3+4x^2+x+4 = x^2(x+4) + (x+4) = (x+4)(x^2+1) Over real coefficients
You may continue over complex value of coefficients to
(x+4)(x+i)(x- i)
You may continue over complex value of coefficients to
(x+4)(x+i)(x- i)
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x^3 + 4x^2 + x + 4 =
x^2(x + 4) + 1(x + 4) =
(x^2 + 1)(x + 4)
x^2(x + 4) + 1(x + 4) =
(x^2 + 1)(x + 4)
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x^3+x+4x^2+4
=x(x^2+1)+4(x^2+1)
=(x+4)(x^2+1).
=x(x^2+1)+4(x^2+1)
=(x+4)(x^2+1).