http://www.wolframalpha.com/input/?i=sum%28%28n%2B1%29%5En%2Fn%5E%28n%2B1%29%29+
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Note that we can rewrite the n-th term as [(n+1)^n / n^n] * (1/n) = (1 + 1/n)^n * (1/n),
and that lim(n→∞) (1 + 1/n)^n = e.
This gives me the idea to use the Limit Comparison Test with the harmonic series.
lim(n→∞) [(1 + 1/n)^n * (1/n)] / (1/n)
= lim(n→∞) (1 + 1/n)^n
= e.
Since the harmonic series diverges, so must the sum in question.
I hope this helps!
and that lim(n→∞) (1 + 1/n)^n = e.
This gives me the idea to use the Limit Comparison Test with the harmonic series.
lim(n→∞) [(1 + 1/n)^n * (1/n)] / (1/n)
= lim(n→∞) (1 + 1/n)^n
= e.
Since the harmonic series diverges, so must the sum in question.
I hope this helps!