Calculate the molar solubility of silver chromate in water at 25°C.
Favorites|Homepage
Subscriptions | sitemap
HOME > > Calculate the molar solubility of silver chromate in water at 25°C.

Calculate the molar solubility of silver chromate in water at 25°C.

[From: ] [author: ] [Date: 11-12-15] [Hit: ]
x = 6.5 x 10^-5 M = [CrO4 2-] = [Ag2CrO4] since 1 mole of Ag2CrO4 contains 1 mole of CrO4 2-.......
Can someone show me how to do this step-by-step? THANK YOU!

-
To answer this you need the Ksp for Ag2CrO4. My textbook says it's 1.1 x 10^-12. When Ksp is stirred into water a very small amount dissolves forming x M CrO4 2- and 2x M Ag+.

Ag2CrO4 <==> 2Ag+ + CrO4 2-

Ksp = [Ag+]2 [CrO4 2-] = (2x)^2 (x) = 4x^3 = 1.1 x 10^-12
x^3 = 2.8 x 10^-13
x = 6.5 x 10^-5 M = [CrO4 2-] = [Ag2CrO4] since 1 mole of Ag2CrO4 contains 1 mole of CrO4 2-.
1
keywords: of,at,silver,solubility,25,water,molar,in,deg,Calculate,chromate,the,Calculate the molar solubility of silver chromate in water at 25°C.
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .