Arc length x=1/2(y^2-4) 1≤y≤4 adding more stuff to get 20 characters
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Arc length x=1/2(y^2-4) 1≤y≤4 adding more stuff to get 20 characters

[From: ] [author: ] [Date: 11-12-15] [Hit: ]
. No problem.......
L = ⌡ √ 1+[ f ' (x) ]² this breaks down to ⌡ √ 1 + y² dx I was wondering if I could use trig identities. I get it to sec(x)^3; the integral of that is ln(sec(x) + tan(x) but subing back in I'm not getting the correct answer.

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The integral of sec^3(x) is not ln|sec(x) + tan(x)|, check again... Use integration by parts making I = the integral of sec^3(x) and integrate twice so you can solve algebraically for I.

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Anytime.. No problem.

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