Why is the radius of a sodium ion (Na+) smaller than the radius of a sodium atom (Na)

Why is the radius of a sodium ion (Na+) smaller than the radius of a sodium atom (Na)?


A. The ion has an excess of electrons, which causes the ion to decrease in size.
B. The ion has gained a proton, which pulls in the electron cloud.
C. The atom loses a valence shell electron to form the ion.
D. The atom has a more equal distribution of charge.

C. The atom loses a valence shell electron to form the ion.
The atom has equal numbers of protons and electrons. The ion has lost an electron thus there are 11 protons and 10 electrons. Since the protons now outnumber the electrons the greater nuclear charge causes the electrons to hunker down closer to the nucleus, hence the ion is smaller than the atom.

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C. It's lost a shell because it's lost an electron to become positive.

Hahaha...cheater!

C. The atom loses a valence shell electron to form the ion.

C