the molar mass of argon is 40 g/mol. What is the molar mass of a gas if it effuses at 0.91 times the speed of argon gas?
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we use Grahame law to solve these problems
(rate1 / rate2 ) ^2 = MM2 / MM1
( rate X / rate Ar ) ^2 = MM Ar / MM X
.91 ^2 = MM Ar / MM X
MM X = 40 / . 8281 = 48.30 g/ mole
(rate1 / rate2 ) ^2 = MM2 / MM1
( rate X / rate Ar ) ^2 = MM Ar / MM X
.91 ^2 = MM Ar / MM X
MM X = 40 / . 8281 = 48.30 g/ mole