When 235U absorbs a neutron, one possible
fission reaction produces 141Ba and 92Kr as products.
How many neutrons are released?
a) 0
b) 1
c) 2
d) 3
e) 4
fission reaction produces 141Ba and 92Kr as products.
How many neutrons are released?
a) 0
b) 1
c) 2
d) 3
e) 4
-
235U + the absorbed neutron = 236 nucleons (neutrons + protons)
141Ba contains 141 nucleons (neutrons + protons)
92Kr contains 92 nucleons (neutrons + protons)
Together these contain 141+92 = 233 nucleons (neutrons + protons)
This means 236 - 233 = 3 nucleons are released.
Since only neutrons (not protons) are released during fission, this means the nucleons are all neutrons. So 3 neutrons are released.
141Ba contains 141 nucleons (neutrons + protons)
92Kr contains 92 nucleons (neutrons + protons)
Together these contain 141+92 = 233 nucleons (neutrons + protons)
This means 236 - 233 = 3 nucleons are released.
Since only neutrons (not protons) are released during fission, this means the nucleons are all neutrons. So 3 neutrons are released.