Find x Solve (x-1)(x-9)=33

Help

x^2 - 9x - x + 9 - 33 = 0
x^2 - 10x - 24 = 0
x^2 - 12x + 2x - 24 = 0
x(x - 12) + 2(x - 12) = 0
(x + 2)(x - 12) = 0
x + 2 = 0 or x - 12 = 0
x = -2 or x = 12

Put the equation back in quadratic form:

x^2 - 10x + 9 = 33
x^2 -10x - 24 = 0


now re-factor:

(x-12)(x+2) = 0

and the answers are 12, -2

i had to solve using the minus B formula so there are two possible values for x
x=-2,12
i hope thats what you were after

x^2 - 10x + 9 = 33
x^2 - 10x - 24 = 0
(x - 12)(x + 2) = 0
x = 12 or x = -2

x² - 10x - 24 = 0
(x - 12)(x + 2) = 0
x = 12 , x = - 2

x1=4
x2=10
so if (4-1)(10-9)=33