Find the area inside one leaf of the rose:
r=6sin(5theta)
r=6sin(5theta)
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Hello
A = 1/2*∫r^2dx
A = 1/2*∫(6sin(5x))^2 dx
A = 1/2[18x - 9/5*sin(10x)]
the first leaf extends from x = 0 to pi/5 , these are the integration borders
A = 1/2*[18pi/5 - 9/5*sin(2pi)]
A = 1/2*[18pi/5 - 0]
A = 5.6546 units^2
Regards
A = 1/2*∫r^2dx
A = 1/2*∫(6sin(5x))^2 dx
A = 1/2[18x - 9/5*sin(10x)]
the first leaf extends from x = 0 to pi/5 , these are the integration borders
A = 1/2*[18pi/5 - 9/5*sin(2pi)]
A = 1/2*[18pi/5 - 0]
A = 5.6546 units^2
Regards