Find the required angular speed (in rpm) of an ultracentrifuge for the radial acceleration of a point 2.50 cm from the axis to equal 400000g.
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Hello
radial acceleration = ω^2R
400 000*9.81 = ω^2*0.025
ω^2 = 1.5696*10^8
ω = 12 528,36 rad/s
ω = 2pif
f = ω/(2pi)
f = 1993.95 rps
f = 1993.95*60 rpm = 119 637 rpm <-- ans
Regards
radial acceleration = ω^2R
400 000*9.81 = ω^2*0.025
ω^2 = 1.5696*10^8
ω = 12 528,36 rad/s
ω = 2pif
f = ω/(2pi)
f = 1993.95 rps
f = 1993.95*60 rpm = 119 637 rpm <-- ans
Regards