a solution of iodine in carbon tetrachloride is 0.10 m. how much carbon tetrachloride must be added to 50mL of this solution to reduce the concentration to 0.025 m (assume volumes are additive)
a. 50mL
b. 100 mL
c. 150 mL
d. 200 mL
a. 50mL
b. 100 mL
c. 150 mL
d. 200 mL
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(0.10 m) x (50mL) / (0.025 m) = 200 mL total solution
(200 mL - 50 mL) = 150 mL to be added, so answer c.
(200 mL - 50 mL) = 150 mL to be added, so answer c.