What is the solution set of the equation...√x + 1 = x - 1
Thanks!!! xoxo
Thanks!!! xoxo
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I concur with the previous answer (Demarie) (take a set of number and just apply them)
though, the whole solution will be any positive interger except zero....
though, the whole solution will be any positive interger except zero....
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x = 4
Solution:
sqrt(4) + 1 = 2 + 1 = 3
x - 1 = 4 - 1 = 3
Solution:
sqrt(4) + 1 = 2 + 1 = 3
x - 1 = 4 - 1 = 3
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To find a solution set you can use any number.
Just pick any 4 numbers and substitute them one by one for x.
The results are your solutions set :)
Just pick any 4 numbers and substitute them one by one for x.
The results are your solutions set :)
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x+1=x^2-2x+1
x^2-3x=0
x=0 is not solution as 1is not equal to -1
x=3 is solution
x^2-3x=0
x=0 is not solution as 1is not equal to -1
x=3 is solution