To find the distance AB across a river, a distance BC=210 is laid off on one side of the river. It is found th
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To find the distance AB across a river, a distance BC=210 is laid off on one side of the river. It is found th

[From: ] [author: ] [Date: 11-12-06] [Hit: ]
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of the river. It is found that B=97 and C=18. Find AB

-
A = 180 - (97 + 18) = 65°

From the law of sines,

AB / sin C = BC / sin A ==> AB = BC sin C / sin A

AB = 210 sin 18 / sin 65 = 71.6 (Answer)
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