the height of an object thrown upward form an initial height h(subscript 0) with an initial velocity(subscript 0) is given by h = -16t(squared) + v(subscript 0)t + h(subscript 0)
The floor of the bridge is 220 ft above sea level. if a rock is thrown upward with a velocity of 30 feet/sec, how long will it take for the rock to hit the water? what does the subscript 0 mean in this equation? how do i plug the stuff in, if someone could please at least set up the plug ins for me i would appreciate it
The floor of the bridge is 220 ft above sea level. if a rock is thrown upward with a velocity of 30 feet/sec, how long will it take for the rock to hit the water? what does the subscript 0 mean in this equation? how do i plug the stuff in, if someone could please at least set up the plug ins for me i would appreciate it
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The subscript 0 is just a way of saying the original point. I forgot what it's called but just disregard it and know that any variable that has it is a constant.
Set the point of reference in this equation to the water's height. If the height of the water is considered to be 0: h is 0 (because it's where the object ends up) h_o_ (or h(subscript 0) as you call it) is 220 ft and v_o_ is 30.
so:
0=-16t^2 +30t +220=-8t^2+15+110
Quadratic theory and there you go. You'll get a positive and negative answer; at that point just decide if time can really be negative.
It's also possible to set the bridge as the reference point. in that case h would be -220, h_o_ would be 0 and everything else is the same. If you plug it in it's obvious it's the exact same thing.
-220 = -16t^2 + 30 + 0
Set the point of reference in this equation to the water's height. If the height of the water is considered to be 0: h is 0 (because it's where the object ends up) h_o_ (or h(subscript 0) as you call it) is 220 ft and v_o_ is 30.
so:
0=-16t^2 +30t +220=-8t^2+15+110
Quadratic theory and there you go. You'll get a positive and negative answer; at that point just decide if time can really be negative.
It's also possible to set the bridge as the reference point. in that case h would be -220, h_o_ would be 0 and everything else is the same. If you plug it in it's obvious it's the exact same thing.
-220 = -16t^2 + 30 + 0