2. Fill in the blank: ln e3 = _____.
9. Solve the following equation for x:
logx +log(x-1) = log(4x)
(Points : 2)
x = 5
x = 0,5 <----- I think it is this one!
x = 1/4log(x - 1)
There are no solutions.
PLEASE UR WORK?
9. Solve the following equation for x:
logx +log(x-1) = log(4x)
(Points : 2)
x = 5
x = 0,5 <----- I think it is this one!
x = 1/4log(x - 1)
There are no solutions.
PLEASE UR WORK?
-
ln e3 = _____
I suppose you mean ln e^3 =
As you know, if log_b (m) = a, then this means that b^a = m, in which "b" is the base of the logarithm. In your example, ln means that the base is "e", so it's like writing log_e (e^3), and therefore the answer is simply 3 because of the property mentioned above.
logx +log(x-1) = log(4x)
log [x(x - 1)] = log(4x)
x(x - 1) = 4x -----> x^2 - x = 4x -----> x^2 - 5x = 0 ----->
x(x - 5) = 0
x1 = 0
x2 = 5
You must ignore the answer x = 0 because when you put it into the original equation you get logarithms of zero or negative numbers, which are undefined. So your answer is x = 5
You see, with x = 5 this is what you get in the original equation:
log 5 + log (5 - 1) = log (4*5)
log 5 + log 4 = log(4*5)
log (5*4) = log (4*5)
log 20 = log 20
So that confirms the answer...
I suppose you mean ln e^3 =
As you know, if log_b (m) = a, then this means that b^a = m, in which "b" is the base of the logarithm. In your example, ln means that the base is "e", so it's like writing log_e (e^3), and therefore the answer is simply 3 because of the property mentioned above.
logx +log(x-1) = log(4x)
log [x(x - 1)] = log(4x)
x(x - 1) = 4x -----> x^2 - x = 4x -----> x^2 - 5x = 0 ----->
x(x - 5) = 0
x1 = 0
x2 = 5
You must ignore the answer x = 0 because when you put it into the original equation you get logarithms of zero or negative numbers, which are undefined. So your answer is x = 5
You see, with x = 5 this is what you get in the original equation:
log 5 + log (5 - 1) = log (4*5)
log 5 + log 4 = log(4*5)
log (5*4) = log (4*5)
log 20 = log 20
So that confirms the answer...
-
For 9, answer is 5.