What is the pressure (in mmHg) of the gas inside the apparatus below if the atmospheric pressure is Patm=765 mmHg, h1=34 mmHg, and h2=64 mmHg?
http://imageshack.us/photo/my-images/235/barometerfig4ow9.jpg/
http://imageshack.us/photo/my-images/235/barometerfig4ow9.jpg/
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Pressure = Patm + rho*g*h
h = h2 - h1
h = 64 mm - 34 cm = 30 mmHg
Patm = 764 mmHg + 30 mmHg
Pressure = 794 mmHg
h = h2 - h1
h = 64 mm - 34 cm = 30 mmHg
Patm = 764 mmHg + 30 mmHg
Pressure = 794 mmHg