Can someone please help how to find with steps ?
Find equation of line passing through (0, -13) parallel to y = (1/3)x - 4
Thanks in advance
Find equation of line passing through (0, -13) parallel to y = (1/3)x - 4
Thanks in advance
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The equation of the line is in slope-intercept form, which is:
y = mx + b
where:
m = slope
b = y-intercept
Parallel lines have the same slope, so we know the slope of the new line will be same as the original, which is 1/3.
The y-intercept is the y value when x=0. Since the point given is (0, -13), -13 is the y-intercept (because x is 0).
So, your parallel line is:
y = (1/3)x - 13
y = mx + b
where:
m = slope
b = y-intercept
Parallel lines have the same slope, so we know the slope of the new line will be same as the original, which is 1/3.
The y-intercept is the y value when x=0. Since the point given is (0, -13), -13 is the y-intercept (because x is 0).
So, your parallel line is:
y = (1/3)x - 13