If two cars are traveling on flat pavement both going in the same direction. The first car is traveling at 65mph and is 500ft ahead of the second car, and the second car is traveling at 84mph. How many seconds will it take the second car to hit the first?
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We first find the difference in speeds of both cars
84-65=19mph
we then convert this speed to feet per hour
1mile=5280 feet
19mph=100320 feet per hour
we then divide the distance by the speed, to see how fast the second car will catch up
500/100320=25/5016 of an hour
we multiply this number by 60 to convert it into minutes, then 60 again to convert it into seconds
25/5016*60*60, we get approximately 18 seconds.
84-65=19mph
we then convert this speed to feet per hour
1mile=5280 feet
19mph=100320 feet per hour
we then divide the distance by the speed, to see how fast the second car will catch up
500/100320=25/5016 of an hour
we multiply this number by 60 to convert it into minutes, then 60 again to convert it into seconds
25/5016*60*60, we get approximately 18 seconds.
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the speed difference 84mph-65mph is 19mph transformed in feet per hour is 100322.15feet/h
if the second car will travel 100322.15 feet more in one hour than the first one for the 500 feet distance from the start it needs ~0.00498h circa 0.29 min or 17.94 ~18 seconds
if the second car will travel 100322.15 feet more in one hour than the first one for the 500 feet distance from the start it needs ~0.00498h circa 0.29 min or 17.94 ~18 seconds
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Do a rate time problem. Rate times time equals distance so rate(time of first) +500=rate(time of second). As they are starting at the same time, their times equal. Therefore 65t+ 500=84t. Solve from there. :-)
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5 seconds, jk thats prob wrong