If sec x = 7 and sin > 0
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If sec x = 7 and sin > 0

[From: ] [author: ] [Date: 11-11-24] [Hit: ]
then it must be in the first quadrant (sin is negative in the fourth quadrant). So the general solution would be arccos(1/7) + 2πn where n is an integer.......
What are the trig functions?

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sec x = 7 → 1 / cosx = 7 → cosx = 1/7
Now solve for x, which could be either in the first quadrant of the fourth quadrant. However, since sin > 0, then it must be in the first quadrant (sin is negative in the fourth quadrant). So the general solution would be arccos(1/7) + 2πn where n is an integer.
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