(-k+1,3), (3,k+3), m=3
Also, write an equation of the line in point slope form
Also, write an equation of the line in point slope form
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m = [k+3 -3]/[3-(-k+1)]
3 = [k]/[k+4]
3(k+4) = k
3k + 12 = k
3k - k = -12
2k = -12
k = -6
3 = [k]/[k+4]
3(k+4) = k
3k + 12 = k
3k - k = -12
2k = -12
k = -6
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(k+3 - 3)/(3+k-1) = 3
k/(2+k) = 3
k = 6+3k
-2k = 6
k = -3
Points are (4,3) and (3,0)
(y-3)/(x-4) = 3
y = 3(x-4)+3
y = 3x - 9
k/(2+k) = 3
k = 6+3k
-2k = 6
k = -3
Points are (4,3) and (3,0)
(y-3)/(x-4) = 3
y = 3(x-4)+3
y = 3x - 9