cot(θ) = sqrt of 3 divided by 3
how do you know what the angle is
i cant seem to figure it out and im not supposed to use a calculator
thanks 10 points
how do you know what the angle is
i cant seem to figure it out and im not supposed to use a calculator
thanks 10 points
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cot θ = √3 / 3 = 1 / √3
tan θ = 1 / cot θ = √3
That's a 60 degree angle.
tan θ = 1 / cot θ = √3
That's a 60 degree angle.
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1/arctan[(sqrt3)/3]
draw a triangle.
leg opp angle is rt3
other leg is 3
draw a 30-60-90 triangle
mult legs & hyp by rt3
since i remember leg opp 30 to be 1, and everything is then mult by rt3,
i should think the answer is 30 degrees
draw a triangle.
leg opp angle is rt3
other leg is 3
draw a 30-60-90 triangle
mult legs & hyp by rt3
since i remember leg opp 30 to be 1, and everything is then mult by rt3,
i should think the answer is 30 degrees
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tan (θ) = 3/sqrt(3) = sqrt(3)
1+ tan^2 (θ) = sec^2 (θ)
1 + 3 = sec^2 (θ)
sec ^2 (θ) = 4
sec (θ) = ±2
cos (θ) = ±1/2
(θ) = pi/3, 4pi/3, 2pi/3 and 5pi/3
To satisfy the original equation
(θ) = pi/3 and 4pi/3 radians
(θ) = 60 and 240 degrees
1+ tan^2 (θ) = sec^2 (θ)
1 + 3 = sec^2 (θ)
sec ^2 (θ) = 4
sec (θ) = ±2
cos (θ) = ±1/2
(θ) = pi/3, 4pi/3, 2pi/3 and 5pi/3
To satisfy the original equation
(θ) = pi/3 and 4pi/3 radians
(θ) = 60 and 240 degrees
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If that was the questions, my teaher would not be asking for the exact angle. It is more accurate just to say that the angle is: sqrt3 over 3, because 3 does not have a whole square root.