When Ume's hockey team uses a "rocket launch" breakout, she has a 55% likelihood of receiving a cross-ice pass while at full speed. While she receives such a pass, the probability of getting her slapshot away is 1/3. Ume's slapshot scores 22% of the time.
What is the probability of Ume scoring with her slapshot when her team tries a rocket launch?
Answer is 121 / 3000 but I have no idea how to get it. The wording of the question confuses me.
Any help is appreciated, thanks so much :)
What is the probability of Ume scoring with her slapshot when her team tries a rocket launch?
Answer is 121 / 3000 but I have no idea how to get it. The wording of the question confuses me.
Any help is appreciated, thanks so much :)
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55% x 1/3 x 22%
= 55/100 x 1/3 x 22/100
= 1210/30000
= 121/3000
= 55/100 x 1/3 x 22/100
= 1210/30000
= 121/3000
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This is a simple dependent probability problem. You are given the probability for each event and each event is dependent on the occurrence of the previous event. So the probability of all the events occuring together is the answer you need.
For eg. Here you are required to find the probability of Ume scoring with her slapshot when her team tries a rocket launch.
So you are asked to find the probability of all the 3 events, i.e. team using rocket launch, Ume getting the slapshot and that slapshot scoring, happening. So you have to find the probability of intersection between all the events.
This will be given by the product of the probabilities of each individual event.
For eg. Here you are required to find the probability of Ume scoring with her slapshot when her team tries a rocket launch.
So you are asked to find the probability of all the 3 events, i.e. team using rocket launch, Ume getting the slapshot and that slapshot scoring, happening. So you have to find the probability of intersection between all the events.
This will be given by the product of the probabilities of each individual event.