f(x) = 10 if x=1, 1/10, 1/100, 1/1000,...
0 otherwise
Explain why lim as x-->0 f(x) does not exist!
0 otherwise
Explain why lim as x-->0 f(x) does not exist!
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For every real ε > 0, there exists a real δ > 0 such that for all real x,
0 < | x − p | < δ implies | f(x) − L | < ε
our case: |f(x) - L| = 0
no lim.
0 < | x − p | < δ implies | f(x) − L | < ε
our case: |f(x) - L| = 0
no lim.