A. 1.26X10 23th power
B. 2.87X10 23th power
C. 6.02X10 23th power
D. 1.26X10 24th power
B. 2.87X10 23th power
C. 6.02X10 23th power
D. 1.26X10 24th power
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First find the moles of At in 100 g
moles = mass / Molar Mass
100 g / 210 g/mol
= 0.47619 moles
To find the number of atoms multiply moles by 6.023 x 10^23 particles per mole
0.47619 mol x 6.023 x 10^23 = 2.87 x 10^23 atoms
moles = mass / Molar Mass
100 g / 210 g/mol
= 0.47619 moles
To find the number of atoms multiply moles by 6.023 x 10^23 particles per mole
0.47619 mol x 6.023 x 10^23 = 2.87 x 10^23 atoms
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B
At-210 is the most stable isotope, so you have 100/210 moles of At.
(100/210)(6.023x10^23) = 2.87x10^23
At-210 is the most stable isotope, so you have 100/210 moles of At.
(100/210)(6.023x10^23) = 2.87x10^23