Okay. heres the thing. my teacher goes too fast for me so i need help. and no i dont want to talk to her so dont suggest that please.
Okay so how do you do y intercept form?
How do you do point slope form?
how do you do standard form?
How do you graph these?
Now these are for linear functions i think so if that helps. thank you and good bye
Okay so how do you do y intercept form?
How do you do point slope form?
how do you do standard form?
How do you graph these?
Now these are for linear functions i think so if that helps. thank you and good bye
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y - intercept form: y = mx + b
m = Slope
b = y - intercept
Point slope form: y - y1 = m(x - x1)
(x1,y1) is a known point.
m = Slope
(x,y) Another point of the line.
Standard Form: Ax + Bx = 0
Graph : y = mx + b
Start on the b, (y - intercept) then find the next point according to the slope.
Slope: Rise/Run
Example:
y = 2x + 2
y - intercept : 2
Slope: 2
Start on the point (0,2) then go up 2 units and 1 right.
m = Slope
b = y - intercept
Point slope form: y - y1 = m(x - x1)
(x1,y1) is a known point.
m = Slope
(x,y) Another point of the line.
Standard Form: Ax + Bx = 0
Graph : y = mx + b
Start on the b, (y - intercept) then find the next point according to the slope.
Slope: Rise/Run
Example:
y = 2x + 2
y - intercept : 2
Slope: 2
Start on the point (0,2) then go up 2 units and 1 right.
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y-intercept: in the form y=mx+b. (m is slope, b is y-intercept) slope is rise over run, so if the slope is 2, when graphing you would go up two spaces and to the right one space (2 is the same as 2/1). If it is negative slope (-2) then you would go up two and to the left one. the y-intercept is where it crosses the y axis (the line vertical) so if the y-intercept was 3 then you would start graphing a 3,0 and then if the slope was 2 then you would go up two and over one. in y-intercept form this example would look like y=2x+3.
point-slope form: in the form y-y1=m(x-x1). this looks confusing. it's not. this is for if you know some points on a line. so lets say that the slope of a line is 2 and it goes through (3,4). 3 is x1 and four is y1. now plug them into the formula so its y-4=3(x-3). simplify and you get y-4=3x-9. simplify more and you get y=3x-5. not graph as you would with y-intercept form
standard form: ax+by=c. this form is for good to find x & y intercepts. lets have an example: 3x+5y=15. to find the x-intercept, you plug in 0 for y. so 3x+5(0)=15. then you get 3x=15 and x=5. so a point on the line in (5,0). then do the same for y-intercept and plug in 0 for x. 3(0)+5y=15. 5y=15 and y=3. the other point is (0,3). now graph the two points and connect the two lines
point-slope form: in the form y-y1=m(x-x1). this looks confusing. it's not. this is for if you know some points on a line. so lets say that the slope of a line is 2 and it goes through (3,4). 3 is x1 and four is y1. now plug them into the formula so its y-4=3(x-3). simplify and you get y-4=3x-9. simplify more and you get y=3x-5. not graph as you would with y-intercept form
standard form: ax+by=c. this form is for good to find x & y intercepts. lets have an example: 3x+5y=15. to find the x-intercept, you plug in 0 for y. so 3x+5(0)=15. then you get 3x=15 and x=5. so a point on the line in (5,0). then do the same for y-intercept and plug in 0 for x. 3(0)+5y=15. 5y=15 and y=3. the other point is (0,3). now graph the two points and connect the two lines