They've given me m = 4, x1 = –1, and y1 = –6. I'll plug these values into the point-slope form, and solve for "y=":
y – y1 = m(x – x1)
y – (–6) = (4)(x – (–1))
y + 6 = 4(x + 1)
y + 6 = 4x + 4
y = 4x + 4 – 6
y = 4x – 2
-to graph, do the same thing as i said in the y-int from
3) standard form(Ax + By = C): A, B, C are integers (positive or negative whole numbers)
No fractions nor decimals in standard form.
Traditionally the "Ax" term is positive.
If there are fractions:
Multiply each term in the equation by the LCD.
Add or subtract to get “x” and “y” on the same side and the number term on the opposite side.
If there are decimals:
Multiply each term in the equation by 10, 100, 1000, etc.
Add or subtract to get “x” and “y” on the same side and the number term on the opposite side.
If there are no fractions nor decimals:
Add or subtract to get “x” and “y” on the same side and the number term on the opposite side.
-to graph, you change it into y-int form and follow the instructions for graphing
Hope this helps!