Homework help! Algebra

I can probably be more help talking to you.......read below.

A).....y - int. form..............y = mx + b

B).....Point slope...............y - y1 = m (x - x1)

C).....Standard..................Ax + By = C

A).....plot the y-intercept and then use the slope

B).....plot the given point and then use the slope

C......Let x = 0, solve for y.......plot that y-intercept
.........Let y = 0, solve for x.......plot that x-intercept

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OK here's how u do it

1) y-int(y=mx+b): solve for y, so if 3y=6x+12 it would be y=2x+4
graphing: you start at B, which is 4 so you go up 4. next, you go up 2 right 1 until you decide you have enough to show what you're doing then you go down 2 left 1
2) point slope: y – y1 = m(x – x1)

Don't let the subscripts scare you. They are just intended to indicate the point they give you. You have the generic "x" and generic "y" that are always in your equation, and then you have the specific x and y from the point they gave you; the specific x and y are what is subscripted in the formula. Here's how you use the point-slope formula:

Find the equation of the straight line that has slope m = 4 and passes through
the point (–1, –6).
This is the same line that I found on the previous page, so I already know what the answer is (namely, y = 4x – 2). But let's see how the process works with the point-slope formula.