07*10^5 km. From these data, determine the mass of the planet.-M = 4π²R³/(G*T²) where T = 1.03*24*3600 = 88992 sec and R = 4.M = 5.......
A small moon of a giant planet has an orbital period of 1.03 days and an orbital radius of 4.07*10^5 km. From these data, determine the mass of the planet.
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M = 4π²R³/(G*T²) where T = 1.03*24*3600 = 88992 sec and R = 4.07E8 m
M = 5.039E27 kg
keywords: and,an,of,small,10,1.03,radius,period,km,orbital,days,moon,has,planet,4.07,giant,A small moon of a giant planet has an orbital period of 1.03 days and an orbital radius of 4.07*10^5 km...
