Given that if f(2)=-1 and f prime-2 =5, find an equation for the tangent line to the graph of y=f(x) at the point where x=2.
Help me out please!!!!!!!!
Help me out please!!!!!!!!
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Okay, if f prime of 2 is five, then you know that that is the slope of the line.
y-y1=m(x-x1) is the tangent line equation.
m=5
x1=2
y1=-1
y+1=5(x-2) is your line! :)
y-y1=m(x-x1) is the tangent line equation.
m=5
x1=2
y1=-1
y+1=5(x-2) is your line! :)
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The point is (2,1) and you are told that the gradient is 5 so the equation of the tangent at (2,1) is
y -1 = 5(x - 2) or y = 5x - 9.
y -1 = 5(x - 2) or y = 5x - 9.