What is the oxidized and reduced in the following

1. 3CN- + H2O + 2MnO4- --> 3CNO- + 2MnO2 + 2OH-

2. K2MnF6 + SbF5 --> KSbF6 + MnF3 + F2

Really having a hard time with these. Will award best answer (if possible, please explain why).

1. CN- = C^4+ N^5- = 1- CNO- = C4+ N^3- O^2- = 1- Therefore N^5- to N^3- (oxid)
MnO4- =Mn^7+ O^8- = 1- Mn4+ , since the oxygens = 4- (redn) It is balanced.

2. Mn = 5+ --> Mn =3+ (redn) 2 F- --> F2^0 (oxid.)