How much heat is required to convert 40g of ice to...

How much heat is required to convert 40g of ice to
A) liquid water at zero degrees and then
B) To raise the temp of melted water to 100 degrees
(molar heat fusion of ice is 6.18kj/mol, specific heat capacity of water = 4.18 J/gc)

Calculate moles of ice 40 g / 18.02 g/mol = 2.2197 mol

Multiply by heat of fusion 2.2197 mol x 6.18 kJ/mol = 14 kJ

Raising the temp of the melted water would then be:

40 g x 4.184 j/goC x 100 oC = 16 736 J or 17 kJ

Total heat = 14 + 17 = 31 kJ