What must be true for an ordered pair to be a solution of a system of two linear equations

I'm having trouble in math....

Ordered pair (x,y) must solve both linear equations. If the two equations are plotted (they will plot as lines) it is the point where both lines intersect.

For an ordered pair to be the solution to a system of linear equations, the pair must simply satisfy all the equations in the system.

For example, the ordered pair (2, -1) is a solution to the following system of linear equations;

2x - 4y = 8 _&_ y = 3x - 7

Plug the ordered pair in, and solve to prove it does indeed fulfill the equations;

2x - 4y = 8

2(2) - 4(-1) = 8
4 - (-4) = 8
4 + 4 = 8
8 = 8


y = 3x - 7
-1 = 3(2) - 7
-1 = 6 - 7
-1 = -1

The ordered pair fulfills both the equations, so it is a solution.

To study this topic more, I would recommend the following site, good luck!

http://www.purplemath.com/modules/systli…

A linear equation is usually expressed: y = mx + b

A linear equation has many possible ordered pairs (x,y) that "solve" the problem. These ordered pairs, say, (0,1), (1,3), (2,5)... all fall on the same line: y = 2x + 1

If two lines (on the same plane, or on the same xy graph) cross, then there will be exactly one ordered pair that is where the two lines cross.

So, can you determine from this information the answer to your question?