Maths differentiation help needed! 10pts!
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > Maths differentiation help needed! 10pts!

Maths differentiation help needed! 10pts!

[From: ] [author: ] [Date: 11-11-19] [Hit: ]
To get this,16x^1 + 7x^0 + 0 (note that x^0 = 1, all constants simply disappear when taking a derivative.In other words,Best of luck!maybe!......
Find dy/dx when y equals:

a) 8x^2 +7x+12
b) 5+4x-5x^2

could you also please show all steps taken, thanks in advance :)

-
Derivatives are relatively simple. You simply multiply the variable by the given power, then reduce the power by 1. For example, given:

x^a

the derivative would be:

a * x^(a-1)

A practical example would be:

2x^5

the derivative is:

5 * 2x^(5-1) = 10x^4

a) 8x^2 + 7x + 12
derivative = 16x + 7

To get this, we have:

2*8x^(2-1) + 1*7x^(1-1) + 0*12x^(0-1) =
16x^1 + 7x^0 + 0 (note that x^0 = 1, all constants simply disappear when taking a derivative. In other words, the derivative of ANY constant = 0)
16x + 7

b) 5 + 4x - 5x^2
derivative is:
0 + 4 - 10x =
4 - 10x

Best of luck!

-
f(x) = au^n
f '(x) = (a) (n) u^(n-1)

a) 8x^2 +7x+12

dy/dx = 8(2)(x^1) + 7 = 16x + 7


b) 5 + 4x + (-5x^2)

dy/dx = 4 + (-5)(2)(x^1) = 4 - 10x

-
a) =(2*8)X + 7
=16X + 7
b) =4 - (5*2)X
=4 - 10X

-
a)-
dy/dx=16x+7

b)-
dy/dx=4-10x


maybe!!!
1
keywords: differentiation,pts,Maths,help,10,needed,Maths differentiation help needed! 10pts!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .