An underground parking lot is being constructed 8.00m below ground level.
A) If the exit ramp is to rise at an angle of 15 degree, how long will the ramp be?
B) What is the horizontal distance, is need for the ramp?
A) If the exit ramp is to rise at an angle of 15 degree, how long will the ramp be?
B) What is the horizontal distance, is need for the ramp?
-
We have a simple right triangle, with the angle of the ramp being 15 degrees, the opposite side being 8.00m and the ramp length being the hypotenuse.
A) Since we know the opposite and want to know the hypotenuse, we use sin:
sin x = opposite / hypotenuse
sin 15 = 8 / ramp
ramp = 8 / sin 15
ramp = 30.91 meters
B) The horizontal distance would be the adjacent side in our triangle, so there are a number of ways we could solve this. We'll use the given opposite of 8.00m, so we want tan:
tan x = opposite / adjacent
tan 15 = 8 / run
run = 8 / tan 15
run = 29.86 meters
Hope this helps!
A) Since we know the opposite and want to know the hypotenuse, we use sin:
sin x = opposite / hypotenuse
sin 15 = 8 / ramp
ramp = 8 / sin 15
ramp = 30.91 meters
B) The horizontal distance would be the adjacent side in our triangle, so there are a number of ways we could solve this. We'll use the given opposite of 8.00m, so we want tan:
tan x = opposite / adjacent
tan 15 = 8 / run
run = 8 / tan 15
run = 29.86 meters
Hope this helps!
-
Let ramp length be X,and horizontal distance Y:
using sine law: (X/SIN90)=(8/SIN15)
then X=(8/SIN15)=30.91m
also (Y/SIN(180-90-15))=(8/SIN15)
then (Y/SIN75)=30.91
Y=29.86m
using sine law: (X/SIN90)=(8/SIN15)
then X=(8/SIN15)=30.91m
also (Y/SIN(180-90-15))=(8/SIN15)
then (Y/SIN75)=30.91
Y=29.86m